4,4′-Bipyridinium tetrachloroaurate(III) chloride
The reaction of gold(III) chloride and 4,4′-bipyridine yields the compound (C10H8N2)[AuCl3] 2, which is converted to the ionic title compound (C 10H10N2)[AuCl4]Cl upon recrystallization from DMSO. The AuIII ion in the tetrachloroaurate anion exhibits a square-planar geometry; this anion is linked to...
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Main Authors: | , , |
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Format: | Article |
Published: |
International Union of Crystallography
2006
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Online Access: | http://eprints.um.edu.my/25291/ https://doi.org/10.1107/S1600536806029199 |
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Summary: | The reaction of gold(III) chloride and 4,4′-bipyridine yields the compound (C10H8N2)[AuCl3] 2, which is converted to the ionic title compound (C 10H10N2)[AuCl4]Cl upon recrystallization from DMSO. The AuIII ion in the tetrachloroaurate anion exhibits a square-planar geometry; this anion is linked to the bipyridinium cation by an N-H⋯Cl hydrogen bond to form chains which extend parallel to the b axis. The bipyridinium cation exhibits 2 symmetry, whereas the tetrachloroaurate anion shows 2/m symmetry, and the chloride anion is located on a position with 222 symmetry. © 2006 International Union of Crystallography. All rights reserved. |
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